Paul is gathering data about moss growth in a local forest. he measured an area of 11 square centimeters on one particular tree and will come back in 6 months to measure the growth of the moss. if the area covered by moss multiplies by one and a half times each month, approximately how much area will the moss cover when paul returns?

The area that moss cover when Paul returns is:

The initial area that is measured by Paul about moss growth in a local forest is:  11 square centimeters.

We know that the increase in the area covered by moss is increasing exponentially.

Since each month it is increasing by a fixed constant 1.5 times as it was the previous month.

Hence, the function which represents the area covered by moss in x months is:

We are asked to find the value of function when x=6

i.e.

            Hence, the answer is:

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1