Which quadratic equation is equivalent to (x + 2)2 + 5(x + 2) - 6 = 0?

The third option

Explanation:
The given expression is:
(x+2)² + 5(x+2) - 6 = 0

Let's check each of the given options:
1- Option A:
(u+2)² + 5(u+2) - 6 = 0
At u = x - 2, the expression would become:
(x-2+2)² + 5(x-2+2) - 6 = 0
x² + 5(x) - 6 = 0 > This option is incorrect

2- Option B:
u² + 4 + 5u - 6 = 0
At u = x-2, the expression would become:
(x-2)²  + 5(x-2) - 2 = 0 > This option is incorrect

3- Option C:
u² + 5u - 6 = 0
At u = x+2, the expression would become:
(x+2)² + 5(x+2) - 6 = 0 > This option is correct

4- Option D:
u² + u - 6 = 0
At u = x+2, the expression would become:
(x+2)² + (x+2) - 6 = 0 > This option is incorrect

Hope this helps :)

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