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Mathematics, 19.07.2019 01:30 aa1000220

Convert the equation to the standard form for a hyperbola by completing the square on x and y. x2 - y2 + 6x - 4y + 4 = 0? (x + 3)2 + (y + 2)2 = 1 (x + 3)2 - (y + 2)2 = 1 (y + 3)2- (x + 2)2 = 1 (y+3)^2/16 − (x+2)^2/36 = 1

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