Segment ef is shown on the graph. what is the x-coordinate of the point that divides ef into a 2: 3 ratio? –3.8 –3.6 1.2 1.4

The picture in the attached figure

we know that
E(-4,-8)   F(9,3)
Find the x-coordinate of the point that divides EF into a 2:3 ratio
let
Rx------> the x-coordinate of the point that divides EF into a 2:3 ratio

(2/5)*EF= ER
(3/5)*EF= RF
ER/RF=2/3

distance EFx=(x2-x1)----> (9+4)----> 13

Rx=Ex+[EFx]*(2/5)
where
Ex is the x coordinate of point E
EFx is the distance x of EF
so
Rx= -4+[13]*(2/5)----> -4+26/5----> (-20+26)/5---> 6/5----> 1.2

the answer is
the x-coordinate of the point is 1.2

Iam not sure , but probably 750 or 7.5