What is the counterexample for the conjecture? conjecture: any number that is divisible by 2 is also divisible by 4. a. 32 b. 12 c. 40 d. 18

Short Answer D

Remark
The answer you want must be factored down to prime factors, two of which are two 2s.

18 = 2 * 3 * 3 There is only one two in this so it is not going to be divisible by 4.

40 = 4 * 10 which = 10 when divided by 4

12 = 3 * 4 which = 3 when divided by 4

32 = 8 * 4 which = 8 when divided by 4  All these last 3 work. Only 18 does not.