Iwill mark brainliest a company produces individually wrapped spherical biscuits. the minimum amount of wrapping material needed to cover a biscuit, assuming no edges overlap, is 200.96 square centimeters. what is the diameter of one biscuit? (use 3.14 for the value of π.)

The minimum amount of wrapping material needed to cover a biscuit would be equal to the biscuit area. The biscuit is spherical/circle, so the area would be using circle formula. If the area is 200,96, the radius would be:
circle area = π * r * r
200.96= 3.14 * r^2
r^2=200.96/3.14
r= √64= 8

The diameter would be: 
diameter = radius *2
diameter= 8*2= 16

The correct awnser is 29.76 pounds.