The area of the base of the oblique pentagonal pyramid is 50 cm^2 and the distance from the apex to the center of the pentagon is 6 square roots of 2cm the measure of angle acb is 45 degrees what is the height of ab

The complete question in the attached figure

Part a) 
we know that
ABC is a right triangle
∠ACB=45°
AC=hypotenuse------> 6√2 cm
sin 45=AB/AC-----> AB=AC*sin 45----> AB=6√2*√2/2----> AB=6 cm

the answer part a) is
AB=6 cm

Part b) 
we know that
volume of the pyramid=(1/3)*Area of the base*height
area of the base=50 cm²
height=6 cm
so
volume of the pyramid=(1/3)*50*6----> 100 cm³

the answer part b) is 
100 cm³

If i’m not wrong i believe it is c