The vertices of a triangle are p(−3, −4), q(3, 4), and r(−6, −3). name the vertices of rx = 0 (pqr). a. p'(3, −4), q'(−3, 4), r'(6, −3) b. p'(−3, −4), q'(3, 4), r'(−6, −3) c. p'(−3, 4), q'(3, −4), r'(−6, 3) d. p'(3, 4), q'(−3, −4), r'(6, 3)

third option: 6x+8

step-by-step explanation:

we can see that the given question is a sum of series and the values of n vary from 0 to 3

the first term will be:

when n=0, [(0)*x+2] => (0+2) => 2

when n=1, [(1)*x+2] => (x+2) => x+2

when n=2, [(2)*x+2] => 2x+2

when n=4, [(3)*x+2] => 3x+2

so adding up all the terms will give us:

=2+x+2+2x+2+3x+2

=x+2x+3x+2+2+2+2

=6x+8

so,

third option is the correct answer ..