Amotorboat in still water travels at a rate of 45 miles per hour. the current today is traveling at a rate of 10 miles per hour. if it took an extra hour to travel upstream, how far was the trip one way?

One way trip was of 157.5 miles.

Step-by-step explanation:

A motorboat in still water travels at a rate of 45 miles per hour.

Velocity of current today = 10 miles per hour

Let distance 'd' is covered in 't' hours by the motorboat in still water.

So the first equation will be

45 =

d = 45t -------------(1)

Now for the second equation

if motorboat travels upstream then the relative velocity of the motorboat will

be = velocity of motorboat in still water - velocity of current

= 45 - 10 = 35 miles/hour  

If motorboat travels upstream it takes extra one hour to cover the same distance.

So the equation will be

35 =

d = 35(t + 1) --------------(2)

Now we equate the value of d in both the equations 1 and 2.

35(t + 1) = 45t

35t + 35 = 45t

45t - 35t = 35

10t = 35

t =

t = 3.5 hours

Now we put t = 3.5 in equation 1

d =  45 × 3.5 = 157.5 miles

One way trip was of 157.5 miles.

answer: 2/4

step-by-step explanation:

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.