Urgent find the equation of the line that passes through the point(4,14) and is parallel to y=5x+3

Hi there!

The general equation of a line in slope-intercept form is y = ax + b. In this equation the variable "a" (the variable in front of "x") represents the slope of the line.

Since our new line is parallel to y = 5x + 3, both lines will have the same slope. Therefore we can already conclude that our line has the equation y = 5x + b.

To find the value of our variable "b", we must plug in the x- and y-coordinate of the point that is on the line. We get the following:

14 = 5*(4) + b
Multiply

14 = 20 + b
Subtract 20.

-6 = b
Eventually switch sides

b = -6
Hence, the equation of the line in slope-intercept form is y = 5x - 6

~ Hope this helps you!

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