The figure below shows a shaded rectangle inside a large rectangle: a rectangle of length 10 units and width 5 units is shown. inside this rectangle is another rectangle of length 9 units and width 3 units placed symmetrically inside the larger rectangle. the smaller rectangle is shaded gray. if you choose a point inside the large rectangle, what is the probability that it is not inside the shaded rectangle?

Step-by-step explanation:

Given : The length of larger rectangle = 10 units

The width of larger rectangle = 5 units

The area of the larger rectangle will be :-

The length of smaller rectangle = 9 units

The width of the smaller rectangle = 3 units

The area of the smaller rectangle will be :-

Now, the probability that it is inside the shaded rectangle :-

Then , the probability that it is not inside the shaded rectangle will be:-

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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step-by-step explanation:

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