Instructions: type the correct answer in each box. use numerals instead of words. if necessary, use / for the fraction bar(s). in this figure, m∠bda = ° and m∠bca = °.

Given

∠ABC is an inscribed angle  

  Find out the  m∠BDA  and m∠BCA .

To proof

First find the value  of the central angle ( intercepted arc measure BA)

∠BOA = 360° - 250°

          =  110 °

Thus the intercepted arc AB is of measure 110°

FORMULA

thus putting the value in the above equation

we get

∠BDA = 55°

Now find out ∠BCA  

In the quadilateral AOBC

As shown in the diagram AC & BD  are tangent

thus

∠CAO = 90°

∠CBO = 90°

As we know the sum of a quadilateral is 360°.

thus

∠AOB + ∠CAO + ∠CBO +∠ BCA  = 360°

Put the value as mentioned above

110° +90° + 90° +∠BCA = 360°

∠BCA = 360° - 290°

∠BCA =  70°

Hence proved

b. 24 mm

step-by-step explanation:

use the pythagorean theorem.

a^2 + b^2 = c^2

a^2 + 7^2 = 25^2

a^2 + 49 = 625

a^2 = 576

a = 24

answer: b. 24 mm

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4