Joseph is standing 12 feet from a mirror lying on the ground, and his eyes are 5 feet above the ground. the line-of-sight reflections on the mirror makes mc003-2.jpg congruent to mc003-3.jpg . if the building is 264 feet from the mirror, which is closest to the height of the building?

See the attached figure which represents the explanation of the problem.
Let the height of the building = h

∵ ∠1 congruent to ∠2
∴ ∠1 = ∠2
∴ tan (∠1) = tan (∠2)    ⇒⇒⇒  tan of the angle =  (opposite/adjacent)

∴
∴ 12 h = 5 * 264 = 1,320
∴ h = 1,320/12 = 110 feet

∴ The height of the building = 110 feet

4038 is the answer lol just use a calculator