Which point lies on the line described by the equation below? y + 3 = 2(x - 1) a. (1,-3) b. (0,0) c. (2,1) d. (2,9) e. (1,-4) ,-6)

Option A is correct that is ( 1 , -3 )

Step-by-step explanation:

Given Equation:

y + 3 = 2(x - 1)

To find: point which lies on line of given equation from given points

A). ( 1 , -3 )

x = 1  , y = -3

LHS = y + 3 = -3 + 3 = 0

RHS = 2(x - 1) = 2(1 - 1) = 0

LHS = RHS

Therefore, This Point lie on the line.

B). ( 0 , 0 )

x = 0  , y = 0

LHS = y + 3 = 0 + 3 = 3

RHS = 2(x - 1) = 2(0 - 1) = -2

LHS ≠ RHS

Therefore, This Point doesn't not lie on the line.

C). ( 2 , 1 )

x = 2  , y = 1

LHS = y + 3 = 1 + 3 = 4

RHS = 2(x - 1) = 2(2 - 1) = 2

LHS ≠ RHS

Therefore, This Point doesn't not lie on the line.

D). ( 2 , 9 )

x = 2  , y = 9

LHS = y + 3 = 9 + 3 = 12

RHS = 2(x - 1) = 2(2 - 1) = 2

LHS ≠ RHS

Therefore, This Point doesn't not lie on the line.

E). ( 1 , -4 )

x = 1  , y = -4

LHS = y + 3 = -4 + 3 = -1

RHS = 2(x - 1) = 2(1 - 1) = 0

LHS ≠ RHS

Therefore, This Point doesn't not lie on the line.

F). ( -1 , -6 )

x = -1  , y = -6

LHS = y + 3 = -6 + 3 = -3

RHS = 2(x - 1) = 2(-1 - 1) = -4

LHS ≠ RHS

Therefore, This Point doesn't not lie on the line.

55/i dont know i do it for the points

step-by-step explanation: