Square rstu is translated to form r's't'u', which has vertices r'(–8, 1), s'(–4, 1), t'(–4, –3), and u'(–8, –3). if point s has coordinates of (3, –5), which point lies on a side of the pre-image, square rstu?

 The options of the question are the points

Step 1

Find the rule of the translation of the pre-image to the image

we know that

the point S has coordinates of

the point S' has coordinates of  

so

a) the rule of the translation of the pre-image to the image is

that means

the translation is units to the left and units up

Step 2

Find the inverse rule of the translation of the image to the pre-image

a) the inverse rule of the translation of the image to the pre-image is

that means

the translation is units to the right and units down

Step 3

Find the coordinates of the vertices of the pre-image

Applying the inverse rule of the translation of the image to the pre-image

a) Point

b) Point

c) Point  

Step 4

Using a graphing tool

graph the points of the pre-image and the points A,B,C and D to determine the solution of the problem

we have

see the attached figure        

therefore        

the answer is

d

step-by-step explanation: