Mathematics, 17.07.2019 13:30 samanthasheets8006

Hurry pls will give 10 pts and which of the following expressions shows how to rewrite 7 − 8 using the additive inverse and displays the expression correctly on a number line? the expression 7 minus negative 8 is written on top. a number line from negative 10 to positive 10 is shown, with numbers labeled at intervals of 1. an arrow is shown from point 0 to 7. another arrow points from 7 to negative 8. the expression 7 minus negative 8 is written on top. a number line from negative 10 to positive 10 is shown, with numbers labeled at intervals of 1. an arrow is shown from point 0 to 7. another arrow points from 7 to 8. the expression 7 plus negative 8 is written on top. a number line from negative 10 to positive 10 is shown with numbers labeled at intervals of 1. an arrow is shown from point 0 to 7. another arrow points from 7 to 1. the expression 7 plus negative 8 is written on top. a number line from negative 10 to positive 10 is shown with numbers labeled at intervals of 1. an arrow is shown from point 0 to 7. another arrow points from 7 to negative 1.

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Answer from: arigamez90

was it right?

Answer from: queeneaf

The addition of numbers on a number line is usually shown by an arrow pointing to the right for positive numbers and an arrow pointing to the left for negative numbers. The length of the arrow corresponds to the size of the number being added.

Here, you are apparently given a diagram that shows 0 + 7 + (-8) = -1. That is, you start at 0, move to the right 7 units as indicated by the arrow of length 7 directed to the right. Then you move to the left 8 units as indicated by the arrow of length 8 from 7 to -1. The ending point of the arrow represents the value of the sum (-1).

The appropriate choice is ...
The expression 7 plus negative 8 is written on top. A number line from negative 10 to positive 10 is shown with numbers labeled at intervals of 1. An arrow is shown from point 0 to 7. Another arrow points from 7 to negative 1.

Answer from: Quest

d) 48

step-by-step explanation:

16,32,48,64,80,96,112,128,144,160,176,192,208,224,240,256,272,288,304,320,336

Answer from: Quest

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

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