What is the equation in point-slope form of the line passing through (3, 6) and (−2, 1)?

a. y + 6 = 1(x + 3)
b. y + 1 = −1(x + 2)
c. y − 6 = −1(x + 3)
d. y − 6 = 1(x − 3)

Y−6=3(x−3)
Explanation:the equation of a line in point-slope form is.∙xy−y1=m(x−x1)where m is the slope and (x1,y1) a point on the lineto calculate the slope m use the gradient formula∙xm=y2−y1x2−x1let (x1,y1)=(3,6) and (x2,y2)=(0,−3)⇒m=−3−60−3=−9−3=3use either of the 2 given points for the point on the lineusing (x1,y1)=(3,6) theny−6=3(x−3)←in point-slope form

Angle onp = 43°angle lno = 137°angle mnp = 137°