Write the equation of the line that passes through (3, 4) and (2, –1) in slope-intercept form. a. y = 3x – 7 b. y = 3x – 5 c. y = 5x – 11 d. y = 5x – 9

1) slope is 6 and y-intercept is ( 0,5)    y = mx + b, m = 6, b = 5    y = 6x + 5 2)line passes through the points ( 3,6) and ( 6,3 )   First find the slope:  m = (3-6)/(6-3) = -3/3 = -1   y = -x + b   Plug in one of the given points (x,y) and find b   6 = -3 + b   9 = b   y = -x + 9 a horizontal line that passes through the point ( -1,7)Horizontal lines have a constant y-value and formaty = c  where c is a constant number. y = 7 y=-3x+3x intercept:  set y = 0 and solve for x0 = -3x + 33x = 3x = 1x-intercept: (1, 0) y-intercept:  set x = 0 and solve for yy = -3(0) + 3y = 3y-intercept: (0,3) y=0,5x-1Is this two equations? The line y=0 has y-intercept at (0,0)The x-intercept is the entire x-axis y=5x-1x -intercept:  Set y = 0 and solve for x y-intercept: Set x = 0 and solve for y 

a - base

b - exponent

so,

the base is 8the exponent is 3the exponent tells you to multiply 8 together three timesthe expanded form is 8*8*8