Alain throws a stone off a bridge into a river below. the stone's height (in meters above the water), xxx seconds after alain threw it, is modeled by: h(x)=-5x^2+10x+15h(x)=−5x 2 +10x+15h, left parenthesis, x, right parenthesis, equals, minus, 5, x, start superscript, 2, end superscript, plus, 10, x, plus, 15 what is the height of the stone at the time it is thrown?

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

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