Supose an investment of 1,800 doubles in value every 7 years. how much is the investment worth after 42 years?

Hey!

First, lets create an equation for your problem.

x  = 

The top part of our equation is the investment value, and the bottom is the years.

Now we have to find out what number times seven is forty-two. Now, if you know your multiplications, this is easy. If you don't, I'll provide a chart for you below.

7 x 1 = 7
7 x 2 = 14
7 x 3 = 21
7 x 4 = 28
7 x 5 = 35
7 x 6 = 42
7 x 7 = 49
7 x 8 = 56
7 x 9 = 63
7 x 10 = 70

Looking at the chart provided, we can see that seven times six equals forty-two. So, we will plug the number 6 into our equation.

x  = 

So, judging by the equation we just created and solved...

The investment is worth  10,800  after 42 years.

Hope this helped!

- Lindsey Frazier ♥

Answer: the correct answer is 10step-by-step explanation: let the number be n, then the expression becomes,then“twelve more than the quotient of a number and two, decreased by four” iswhen n=4,we substitute 4 whetever we see n to get,we simplify to obtain,we further simplify to get,therefore the correct answer is c.