1. use the equation x+2= square root 3x+10 to answer these questions. a. what it the solution to the equation? b. what is the extraneous solution. why? c. in general, what is an extraneous solution? 2. the equation x+2= square root 3x+10 is of the form x+a= square root bx+c, where a, b, and c are all positive integers and b> 1. using this equation as a model, create your own equation that has extraneous solutions. a. using trial and error with numbers for a, b, and c, create an equation of the form x+a= square root bx+c, where a, b, and c are all positive integers and b> 1 such that 7 is a solution. (hint: substitute 7 for x, and choose a value for a. then square both sides so that you can choose a, b, and c that will make the equation true) b. solve the equation you created in a c. if your solution in part b did not have an extraneous solution, revise your equation so that 7 is one solution and there is an extraneous solution. if your solution in part b did have an extraneous solution, create another equation with different values of a, b, and c that also has 7 as one solution and an extraneous solution.