Geometry . i would like it if you would show work

AB=sqrt(53)

Step-by-step explanation:

consider the right angle triangle of the top rectangle w sides of 6 n 4

diagonal^2 = 6^2 + 4^2

consider the right angle triangle of the diagonal, AB and 1

AB^2 = diagonal^2 + 1^2

= 6^2 + 4^2 + 1^2

= 36 + 16 + 1

=53

AB=sqrt(53)

ans is a

b

step-by-step explanation:

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk