Mathematics, 17.07.2019 03:00 toyensianelys130
2sin^2 2x=2 in the domain [0,2pi) what can x equal ( in radians).
Answers: 1
![\bf 2sin^2(2x)=2\implies sin^2(2x)=\cfrac{2}{2} \\\\\\ sin^2(2x)=1\implies [sin(2x)]^2=1\implies sin(2x)=\pm\sqrt{1} \\\\\\ sin(2x)=\pm 1\implies sin^{-1}[sin(2x)]=sin^{-1}(\pm 1)](/tpl/images/0098/5757/e4b3d.png)
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2sin^2 2x=2 in the domain [0,2pi) what can x equal ( in radians)....
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