The sum of two numbers is 64. one number is five less than the twice the other. find the larger number.

Hello!

To find the answer, we will use a system of equations representing the scenario and solve using substitutions, where L represents the larger number, and s represents the smaller number.

L=2s-5
L+s=64

Since we see that L=2s-5, lets plug it into the second equation and solve for s.

2s-5+s=64
3s-5=64
3s=69
s=23

Now with the value for s, we can find the value for L.

L=46-5
L=41

We have found the value, but let's check with the first equation just to make sure this is the correct value.

41+23=64

The larger number is 41.

I hope this helps!