When the product of 6 and the square of a number is increased by 5 times the number, the result is 4. select all of the values that the number could be.

The product of 6 and the square of a number is increased by 5 times the number, the result is 4.

Let's represent the number as y

The algebraic expression for the above sentence is written as:

(6 x y²) + 5y = 4

6y² + 5y = 4

The above expression can also be written as:

6y² + 5y - 4 = 0

We have to factorize the above expression to solve for y

6y² - 3y + 8y - 4 = 0

3y (2y - 1) + 4(2y + 1) = 0

(3y + 4)(2y - 1) = 0

Solving for y

3y + 4 = 0

3y = -4

Divide both sides by 3

3y/3 = -4/3

y =

or

2y - 1 = 0

2y = 1

Divide both sides by 2

2y/2 = 1/2

y =

Therefore, the values that the number could be is given as  

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your answer is 228

step-by-step explanation:

add the top and bottom bases together, then divide them by 2, then multiply by the height.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.