Some one integrate me this [ (x²+1)/(x⁴-1)]

Answer:     ∫(x²+1)/(x⁴-1)dx is equal to    ======    note that, by difference of squares, x⁴-1 = (x²+1)(x²-1), so    (x²+1) cancel so we are left with    we can  break down  into partial fractionssince there are two linear factors in the denominator, x + 1 and x - 1, we have the following partial fraction decomposition:     we are trying to make an identity because we want to change the form of  into a decomposed partial fraction form. therefore, this equation is true for all values of x.to find the values of a and b, we can start by multiplying both sides of the equation by the lowest common denominator, (x+1)(x-1).    we can use a shortcut for linear factors.  since this equation is an identity and true for all values of x, we can use any value of x to us try to find the values of a and b that will establish this identity.if we choose x = 1, we can eliminate a and solve for b:     if we choose x = -1, we can eliminate b and solve for a    therefore:     and we have