Two people are standing on opposite sides of a hill. person a makes an angle of elevation of 65° with the top of the hill and person b makes an angle of elevation of 80° with the top of the hill. the two people are standing 45 feet from each other. what is the distance from person b to the top of the hill?

See the picture to better understand the problem

we know that
in the triangle ABC
∠A+∠B+∠C=180°
find ∠C
∠C=180-[80+65]------> ∠C=35°

Applying the law of sines

AB/sin C=CB/sin A
solve for CB
CB=AB*sin A/sin C-----> CB=45*sin 65/sin 35-----> CB=71.10 ft

the answer is
the distance from person B to the top of the hill is 71.10 feet

Im sorry but what on

Your maths is very weak try yourself this would improve your skills don't depend on others