Me its a huge emergency which of the following statements have the same result? explain each step in solving each one. i. f(2) when f(x) = 3x + 2 ii. f-1(3) when f(x) = 2 x minus 7, all over 3 iii. 2y + 14 = 4y − 2

I.
First, plug in the number two in the place of x.
f(2) = 3(2) + 2.
Simplify
f(2) = 6+2
f(2) = 8

II.
First, we need to find the inverse function of x.
To do this, we begin by replacing f(x) with y, and switching the x and y values.
y= (2x-7)/3
x= (2y-7)/3
Then we solve for y.
3x = 2y-7
3x + 7 = 2y
(3x+7)/2 = y
Replace y with f^-1(x)
f^-1(x)= (3x+7)/2
Now that we have the inverse function, plug in 3 for x.
f^-1(x) = (3(3) + 7)/2
f^-1(x) = (9+7)/2
f^-1(x) = 16/2 = 8.

III. 2y+14 = 4y-2
Solve for y
14 = 2y - 2
16 = 2y
y = 8

So, since all of the statements have the result of 8, then all the statements have  the same result.

Hope this helps!

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