Which ordered pair makes both inequalities true? y > –2x + 3 y < x – 2 (0,0) (0,–1) (1,1) (3,0)

(3,0)

Step-by-step explanation:

Given system of inequalities,

y > -2x + 3

y < x - 2

At (0,0),

0 > -2(0) + 3     ( False )

0 < 0 - 2           ( False )

At (0, -1),

- 1 > -2(0) + 3    ( False )

-1 < 0 - 2           ( False )

At (1, 1),

1 > -2(1) + 3      ( False )

1 < 1 - 2            ( False )

At (3, 0),

0 > -2(3) + 3     ( True )

0 < 3 - 2           ( True )

Hence, the order pair (3, 0)  makes both inequalities true.

Last option is correct.

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

1) is right

step-by-step explanation: