1. ab is tangent to circle o at b. the diagram is not drawn to scale. if ab = 6 and ao = 11.7, what is the length of the radius (r)? round the answer to the nearest tenth. a. 5.7. b. 8.9. c. 10.0. d. 13.1. if you have all the answers feel free to write them below. it is connections academy lesson 7: circles unit test unit 7

the picture in the attached figure

we know that

if AB is tangent to circle O at B

then 

OB is the radius and is perpendicular to AB

therefore

in the right triangle ABO

applying the Pythagoras Theorem

AO²=AB²+OB²-------> solve for OB

OB²=AO²-AB²------> 11.7²-6²------> OB²=100.89

OB=√100.89--------> OB=10.04----------> OB=10.0 units

the answer is the option

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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