Acomic-strip writer churns out different numbers of comic strips each day. the writer logged the number of comic strips he wrote each day for 16 days and sorted the data in ascending order to create this data set. {1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 6, 8} the skew in the distribution is . if the writer writes for two more days and creates 5 and 7 comic strips, respectively, the difference of the mean and the median for the new data set is .

Step-by-step explanation:

Given that a comic-strip writer churns out different numbers of comic strips each day. The writer logged the number of comic strips he wrote each day for 16 days and sorted the data in ascending order to create this data set.

1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 6, 8

Mean = 3.77 and median =3.5

When mean > median, hence positively skewed.

skewness = 0.74

If 5 and 7 are added the data set in ascending order is

1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5,5. 6, 7,8

Mean = 3.7778 and median = 3.5

Difference of mean =0.0078 and

difference of median = 0

a - base

b - exponent

so,

about 0.75 hours

step-by-step explanation: