Arectangle has an area of 40 square units. the length is 6 units greater than the width. what’s are the dimensions of the rectangle?

Width of the rectangle is 4 units and length is 10 units

Step-by-step explanation:

Area of the rectangle = length × width

⇒ 40 = x (6 + x)

⇒ 40 = 6x + x²

⇒ x² + 6x - 40 = 0

⇒ x² + 10x - 4x - 40 = 0 (Using Product Sum rule to factorize)

⇒ x(x + 10) - 4(x + 10) = 0

⇒ (x + 10)(x - 4) = 0

⇒ x = -10, 4 (negative value is neglected)

x = 4 and 6 + x = 10

good job you smart son of a gun you are smarter that einstein. 7

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl