Answer i need done in the figure, oa = r and oc = r. the sector cob is cut from the circle with center o. the ratio of the area of the sector removed from the outer circle to the area of the sector removed from the inner circle is . r^2/r^2 r/r (r^2 - r^2)/r^2 1

The picture in the attached figure

we know that
area of a sector=(∅/2)*r²--------> when ∅ is in radians

area of sector inner circle=(∅/2)*r²

area of sector outer circle=(∅/2)*R²-(∅/2)*r²

The ratio of the area of the sector removed from the outer circle to the area of the sector removed from the inner circle is
[(∅/2)*R²-(∅/2)*r²]/[(∅/2)*r²]-----> [R²-r²]/[r²]

therefore

the answer is
(R^2 - r^2)/r^2

Jjutsclopyrsvnkiu it’s c

Answercounterclockwise rotation about the origin by 180 degrees followed by reflection about the y-axisexplanationthe given figure has verticesrecall that for counterclockwise rotation about the origin, when we rotate figure pqrs counterclockwise through an angle of 180° about the origin, the coordinates will becomenext, we reflect in the y-axis by negating the x-coordinates of the resulting figure to obtain,therefore the correct answer is c