Line jk passes through points j(–4, –5) and k(–6, 3). if the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b?

Hello!

First of all we solve for the slope as seen below.



Our slope is -4.

Now we substitute a point from our equation into slope intercept form, along with the slope. Then we solve for b. We will use (-4,-5)

-5=-4(-4)+b
-5=16+b
b=-21

Our final equation is shown below.

y=-4x-21

I hope this helps!

1. 3/6 or 1/22. 1/123. 1/84. 1/105. 2/12 or 1/6