Write the equation of the transformed graph of sine with period pi that has been shifted vertically up 3 unit and has an amplitude of 3/4

Step-by-step explanation:

We have the function,

It is required to form a function with period , shifted vertically 3 units upwards and having amplitude =

Now, as we know, 'If a function f(x) has the period P, then f(bx) will have period '.

Since, the new function need to have period , that is the value i.e. .

So, b= 2 implies the new function is

Further, as the function need to be vertically shifted 3 units upwards, we get the new function,  .

Finally, the amplitude of the function must be , this means that the maximum and minimum value of the function is and .

This gives us the transformed final function is .

answer:   b

step-by-step explanation:

x2 = 16

x can not be a negative number because 16 is positive

the only answer would be positive 8  

1/8 3/16 3/4

step-by-step explanation:

you put them as all the same denominator and multiply