Mathematics, 16.07.2019 09:00 evelinn19
Given: abc is a triangle. prove: bc + ac > ba in triangle abc, we can draw a perpendicular line segment from vertex c to segment ab. the intersection of ab and the perpendicular is called e. we know that be is the shortest distance from b to and that is the shortest distance from a to ce because of the shortest distance theorem. therefore, bc > be and ac > ae. next, add the inequalities: bc + ac > be + ae. then, be + ae = ba because of the . therefore, ba + ac > ba by substitution.
Answers: 2
Mathematics, 21.06.2019 21:00
The zoo collects $9.60 for every 24 tickets sold. how much will be collected for 400 tickets?
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Mathematics, 21.06.2019 22:00
(05.03 mc) part a: explain why the x-coordinates of the points where the graphs of the equations y = 4x and y = 2x−2 intersect are the solutions of the equation 4x = 2x−2. (4 points) part b: make tables to find the solution to 4x = 2x−2. take the integer values of x between −3 and 3. (4 points) part c: how can you solve the equation 4x = 2x−2 graphically? (2 points)
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Mathematics, 21.06.2019 22:30
Which of the following is an example of a rational number? a. π b. √ 9 c. √ 8 d. 3.8362319
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Given: abc is a triangle. prove: bc + ac > ba in triangle abc, we can draw a perpendicular lin...
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