The x-intercepts of the gravy of f (x)= x (x+1)(x-5)(x-7) are

"Of the gravy" lol

To find the x-intercepts, you make f(x) = 0 and solve for x by setting each factor equal to 0. 

0 = x(x + 1)(x - 5)(x - 7)

x = 0

x + 1 = 0
x = - 1

x - 5 = 0
x = 5

x - 7 = 0
x = 7

Your x-intercepts are x = - 1, 0, 5, 7

OR

There are x-intercepts at (- 1, 0), (0, 0), (5, 0), and (7, 0).