The projectile motion of an object can be modeled using h(t) = gt2 + v0t + h0, where g is the acceleration due to gravity, t is the time since launch, h(t) is the height of the projectile after time t, v0 is the initial velocity, and h0 is the initial height. the acceleration due to gravity is –9.8 m/s2. an object is launched at an initial velocity of 20 meters per second and an initial height of 60 meters.

option C

Step-by-step explanation:

The projectile motion of an object can be modeled using h(t) = gt2 + v0t + h0, where g is the acceleration due to gravity. The acceleration due to gravity is –9.8 m/s2

An object is launched at an initial velocity of 20 meters per second and an initial height of 60 meters.

g= -9.8, v0 = 20  and h0 = 60

So the equation becomes

When the object hit the ground the height =0 so we replace h(t)=0

Apply quadratic formula

a= -9.8 , b=20  and c= 60

1d

2b

3 false

4 d

5 3200sq,ft

80+60+y=180

then divide the difference between 60 and y and add it to 180

so x =180 +( (y-60)/2)

x equals 200

step-by-step explanation:

8

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.