The sum of three consecutive consecutive integers is 141 what is the smallest integer

Our three consecutive integers can be represented as

X → first integer

X + 1 → second integer

X + 2 → third integer

If the sum of our three consecutive integers is 141, our equation will read...

X + X + 1 + X + 2 = 141

Now, we can simplify on the left. Once we simplify, our equation will now read

3x + 3 = 141

      -3     -3  ← subtract 3 on both sides

      3x = 138 ← divide by 3 on both sides

       X = 46 ← smallest integer

Therefore, the smallest integer is 46.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.