The quadratic x^2+440x+440^2 can be written in the form (x+b)^2+c, where b and c are constants. what is c/b?

This form (x+b)²+c is a vertex form that can be found by completing square for the equation x²+440x+440².

To complete square we will need to use formula  a² +2ab + b² = (a+b)²

 x²+440x+440²,
x² +2*220²x +220² -220² +440²  (we added 220² -220², so nothing really changed here).

x² +2*220²x +220² -220² +440² ( here , bold part can be rewritten as (x+220)²)

(x+220)² -220² +440² (calculating bold part)
 
(x+220)² -220² +440² = (x+220)²  + 145200

Now we have  x²+440x+440², in the form that we need 
 x²+440x+440² = (x+220)²  + 145200

(x+b)²+c = (x+220)²  + 145200,
b=220,
c= 145200

So, 
c/b = 145200/220 = 660
c/b = 660/1 (if you need it in a fraction form)  or 660.

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!