Point m is the midpoint of segment ab. if am = 50 – 3x and mb = –20 + 4x, find the value of am am = -10 am = 10 am = -20 am = 20

If M is the midpoint of segment AB then |AM| = |MB|
|AM| = 50 - 3x|BM| = -20 + 4x

We have the equation:

50 - 3x = -20 + 4x    |-50
-3x = -70 + 4x    |-4x
-7x = -70    |:(-7)
x = 10
|AM| = 50 - 3x
substitute the value of x:
|AM| = 50 - 3 · 10 = 50 - 30 = 20
AM = 20

Ibelieve it would be letter c (:

Sin(a)+cos(a)+cot(a)-1=2(csc(x)+1)