Which rule represents the translation form the pre image abc to the image a’b’c’

The rest of the question is the attached figure.

As shown in the graph
The coordinates of the image ABC are:
A(-3,4) , B(-4,1) and C(-2,1)

And the coordinates of A'B'C' are:
A'(4,-2) , B'(3,-5) and C'(5,-5)

So,
A' - A = (4,-2) - (-3,4) = (7,-6) →(1)
B' - B = (3,-5) - (-4,1) = (7,-6) →(2)
C' - C = (5,-5) - (-2,1) = (7,-6) →(3)

So, from (1), (2) and (3)

The rule represents the translation form the pre image ABC to the image A’B’C’ is ⇒⇒⇒ (x, y) → (x + 7, y – 6)

The answer would be choice b