Mathematics, 15.07.2019 20:30 Aidanme25
To three decimal places, find the average value of f(x) = 2x2 + 3 on the interval [0, 2].
Answers: 1
where b is the upper bound and a is the lower. For us, this formula will be filled in accordingly. 
. We will integrate that now: ![\frac{1}{2}[ \frac{2x^3}{3}+3x]](/tpl/images/0093/7609/9f654.png)
from 0 to 2. Filling in our upper and lower bounds we have ![\frac{1}{2}[( \frac{2(2^3)}{3}+3(2))-0]](/tpl/images/0093/7609/60b95.png)
which simplifies to 
and 
which is 17/3 or 5.667
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To three decimal places, find the average value of f(x) = 2x2 + 3 on the interval [0, 2]....
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