The hypotenuse of a 45°-45°-90° triangle measures 22 square root of 2 units. what is the length of one leg of the triangle?

This is a case of a Special triangle of 45, 45 and 90 degrees, in this cases  the two legs with be equal.
 if the hypotenuse is 22, then divide by the square root of 2, and you will get 15.6 if we round it to the nearest tenth

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm

Yes, two vertical lines can be complementary