Aregular octagon has side length 10.9 in. the perimeter of the octagon is 87.2 in cm and the area is 573.67 in2. a second octagon has side lengths equal to 21.8 in. find the area of the second octagon. round to the nearest hundredth

To solve this problem you must apply the proccedure shown below:

1. If the first octagon and the second octagon are similar, you need to find the ratio of the lengths, as below:

2. The ratio of the area is:

4. Then, you must multiply the ratio by the area of the first octagon to calculate the second area:

The answer is:

-14

step-by-step explanation:

2x2 – 2(x+4)

=2x2-2（5+4）

=4-2×9

=4-18

=-14

john earns $14.00 for two hours of work.