Determine the discriminant for the equation -3=x^2+4x+1 based on the discrimininant value how many real solutions does the equation have

-3 = x^2 + 4x + 1 

Add 3 to both sides.

0 = x^2 + 4x + 4

Switch sides.

x^2 + 4x + 4 = 0

For the quadratic formula, a = 1, b = 4, c = 4

discriminant = b^2 - 4ac = 4^2 - 4(1)(4) = 16 - 16 = 0

When the discriminant equals zero, there is a single real solution.

There is a single, real solution.

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