Ms. jones is ordering pizzas for the school dance. to keep things simple, she plans on only ordering two types, cheese and pepperoni. each cheese pizza costs $10 and each pepperoni pizza costs $13. the number of cheese pizzas should be more than twice the number of pepperoni pizzas. the school dance budget will allow for no more than $200 to pay for the pizzas. this situation can be modeled by the following system of inequalities. 10x + 13y < 200 x > 2y a. the system represents the minimum amount that ms. jones can spend on pepperoni pizzas, x, and cheese pizzas, y, and the relationship between the number of cheese pizzas and pepperoni pizzas. b. the system represents the minimum amount that ms. jones can spend on cheese pizzas, x, and pepperoni pizzas, y, and the relationship between the number of cheese pizzas and pepperoni pizzas. c. the system represents the maximum amount that ms. jones can spend on pepperoni pizzas, x, and cheese pizzas, y, and the relationship between the number of cheese pizzas and pepperoni pizzas. d. the system represents the maximum amount that ms. jones can spend on cheese pizzas, x, and pepperoni pizzas, y, and the relationship between the number of cheese pizzas and pepperoni pizzas.

Option C

Step-by-step explanation:

Given that Ms. Jones is ordering pizzas for the school dance. To keep things simple, she plans on only ordering two types, cheese and pepperoni. Each cheese pizza costs $10 and each pepperoni pizza costs $13. The number of cheese pizzas should be more than twice the number of pepperoni pizzas.

The constraints in inequality form are

10x+13y<200 and x>2y

The first equation represents the maximum amount that Mr. jones can spend on pepperoni pizzas, x, and cheese pizzas, y.

The second equation represents the relationship between the number of cheese pizzas and pepperoni pizzas.

Hence we find that option C is the correct answer.

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.