Asap a quadratic function models the graph of a parabola. the quadratic functions, y = x2 and y = x2 + 3, are modeled in the graphs of the parabolas shown below. determine which situations best represent the scenario shown in the graph of the quadratic functions, y = x2 and y = x2 + 3. select all that apply. the quadratic function, y = x2, has an x-intercept at the origin the quadratic function, y = x2 + 3, has an x-intercept at the origin from x = -2 to x = 0, the average rate of change for both functions is positive from x = -2 to x = 0, the average rate of change for both functions is negative for the quadratic function, y = x2, the coordinate (2, 3) is a solution to the equation of the function. for the quadratic function, y = x2 + 3, the coordinate (2, 7) is a solution to the equation of the function.

View the attached photo.

The quadratic function, y = x2, has an x-intercept at the origin  = TRUE

The quadratic function, y = x2 + 3, has an x-intercept at the origin = FALSE

From x = -2 to x = 0, the average rate of change for both functions is positive = FALSE

When viewing a graph, you start from the left and go to right and from left to right from -2 to 0 the graph is declining.

From x = -2 to x = 0, the average rate of change for both functions is negative = TRUE

Both are declining if you read the graph from left to right.

For the quadratic function, y = x2, the coordinate (2, 3) is a solution to the equation of the function. = FALSE

y = x^2
If we insert 2 into y = x^2 we get y = 4 but our point (2,3) has y = 3

For the quadratic function, y = x2 + 3, the coordinate (2, 7) is a solution to the equation of the function. = TRUE

If we insert 2 for x, we see that  y = x^2 + 3 =  y = 2^2 + 3 =  y = 7 and our y value in the point (2,7) is 7. 

I'm pretty sure it's b). i try drawing the functions out and b is the one that stands out or isnt a "line"