Peter can drive 25mph faster on the highway than he can on country roads. in the same time it would take peter to drive 70 mi on the country roads. he could, drive 120 mi on the highway . how fast can he drive on each type of road?

Let

x> Peter's drive speed on the highway in mph

y> Peter's drive speed on country roads in mph

we know that

x=25+y> equation 1

70/y=120/x> 70*x=120*y> x=120*y/70> equation 2

remember that

time=distance/speed

equate equation 1 and equation 2

25+y=120*y/70> multiply by 70 both sides

70*[25+y]=120*y> 1,750+70*y=120*y> 50*y=1,750> y=35 mph

x=25+35> x=60 mph

the answer is

Peter's drive speed on the highway is 60 mph

Peter's drive speed on country roads is 35 mph

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages