Apool in the shape of a rectangle has a perimeter of 80feet. the pool is 8 feet less wide than it is long. find the length and width of the pool

The length and width of the pool = 24 ft and 16 ft

Step-by-step explanation:

Let length of pool be l and width of pool be w.

A pool in the shape of a rectangle has a perimeter of 80feet.

Perimeter of pool = 2 x ( l + w ) = 80 feet

That is

       l + w  = 40 ft eqn 1.

The pool is 8 feet less wide than it is long.      

      l = 8 + w

       l - w  = 8 ft eqn 2.      

eqn 1 + eqn 2

        2 l = 48

         l = 24 ft

Substituting

         24 + w = 40

         w = 16 ft

The length and width of the pool = 24 ft and 16 ft

the answer is true.

step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it